0=-4.9t^2+24.5t+9.6

Solution for 0=-4.9t^2+24.5t+9.6 equation:

0=-4.9t^2+24.5t+9.6

We move all terms to the left:

0-(-4.9t^2+24.5t+9.6)=0

We add all the numbers together, and all the variables

-(-4.9t^2+24.5t+9.6)=0

We get rid of parentheses

4.9t^2-24.5t-9.6=0

a = 4.9; b = -24.5; c = -9.6;
Δ = b2-4ac
Δ = -24.52-4·4.9·(-9.6)
Δ = 788.41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24.5)-\sqrt{788.41}}{2*4.9}=\frac{24.5-\sqrt{788.41}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24.5)+\sqrt{788.41}}{2*4.9}=\frac{24.5+\sqrt{788.41}}{9.8}
$